Superposition(Hurry in a rush)

Discussion in 'Homework Help' started by SHuzero, Feb 23, 2011.

  1. SHuzero

    Thread Starter New Member

    Feb 22, 2011
    14
    0
    please help me to answer this circuit to superposition.... q1.JPG
     
  2. Robert.Adams

    Active Member

    Feb 16, 2010
    112
    5
    What exactly do you need help on? To use superposition you just look at each source's contribution one at a time while disabling the others (short voltage sources, open current sources).

    Edit: Sorry, didn't see the 3 Ohm resistor in there. Just an example of applying superposition is the contribution from the 15V supply; When the 10V is shorted and the 3A is opened, the 15V flows through 5 ohms and 6 ohms in series and then into a parallel combination of 3 and 7 ohms. Therefore we have 15/(6+5+(7//3)) for the 15V contribution to Iy.
     
    Last edited: Feb 23, 2011
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