Superposition(Hurry in a rush)

Discussion in 'Homework Help' started by SHuzero, Feb 23, 2011.

  1. SHuzero

    Thread Starter New Member

    Feb 22, 2011
    please help me to answer this circuit to superposition.... q1.JPG
  2. Robert.Adams

    Active Member

    Feb 16, 2010
    What exactly do you need help on? To use superposition you just look at each source's contribution one at a time while disabling the others (short voltage sources, open current sources).

    Edit: Sorry, didn't see the 3 Ohm resistor in there. Just an example of applying superposition is the contribution from the 15V supply; When the 10V is shorted and the 3A is opened, the 15V flows through 5 ohms and 6 ohms in series and then into a parallel combination of 3 and 7 ohms. Therefore we have 15/(6+5+(7//3)) for the 15V contribution to Iy.
    Last edited: Feb 23, 2011