supercapacitor battery

Thread Starter

rasakumar

Joined Nov 26, 2016
1
i want to assemble a 48v supercapacitor battery for using in electric bike. what are the other things required for assembling in addition to super capacitors?
 

crutschow

Joined Mar 14, 2008
34,285
A battery.
Supercapacitors cannot store enough energy to power your bike for any significant time.
Supercapacitors store much less energy than an equivalent size and weight battery.
 

WBahn

Joined Mar 31, 2012
29,979
i want to assemble a 48v supercapacitor battery for using in electric bike. what are the other things required for assembling in addition to super capacitors?
A very large trailer to put all those supercaps on.

Let's just do a simple computation to see what capacitance would be needed to store the amount of energy that is stored in a single D-cell alkaline battery. The amp-hour rating of the D-cell is approximately 17 A·h, which works out to about 75 kJ (since the terminal voltage decreases as the battery is drained).

http://www.allaboutbatteries.com/Energy-tables.html

To match that at the nominal 1.5 V terminal voltage a capacitor would have to be 100,000 farads. Now consider how far you could possibly expect to get on an electric bike powered by a single alkaline D-cell.
 

anhnha

Joined Apr 19, 2012
905
A very large trailer to put all those supercaps on.

Let's just do a simple computation to see what capacitance would be needed to store the amount of energy that is stored in a single D-cell alkaline battery. The amp-hour rating of the D-cell is approximately 17 A·h, which works out to about 75 kJ (since the terminal voltage decreases as the battery is drained).

http://www.allaboutbatteries.com/Energy-tables.html

To match that at the nominal 1.5 V terminal voltage a capacitor would have to be 100,000 farads. Now consider how far you could possibly expect to get on an electric bike powered by a single alkaline D-cell.
How did you get 100, 000 farads? Thanks.

E = 1/2* CV^2 = 75kJ where V = 1.5V. I got C about 66,666 farads.
 

WBahn

Joined Mar 31, 2012
29,979
How did you get 100, 000 farads? Thanks.

E = 1/2* CV^2 = 75kJ where V = 1.5V. I got C about 66,666 farads.
You're correct. I did the math in my head and although I checked the units mentally on dividing by (1.5 V)², I only divided by 1.5 once (I was probably too impressed with that coming out to such a nice, round figure). The point is still quite valid though. Thanks for checking the math and pointing out the error.
 
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