it is vey low current (5 milli amp) and max out put voltage is 10 vHow much current for the output of the voltages stepped and what is the MAX output voltage ? Can you use mcu or just discrete logic chips ?
Allen
After reach 10 v it stays and reset and start again when I enabled againWhat do you want it to do after it reaches 10V, reset and start again from 0V?
it works perfect , thanks so muchBelow is the simulation of a circuit, as Scott suggested, with a 555 clock, a binary counter, and an R-2R ladder network with an op amp and transistor buffer output that gives ten 1V, 1 second steps and then repeats.
Is that more or less what you want?
Edit: The +12V power and ground connections to the counter and the AND gate are not shown.
Note that for best accuracy/stability you can use two 10kΩ resistors in series to make the 20kΩ resistance values. That also simplifies the part's list, although at the expense of more parts.
View attachment 71799
what is the function of the transistor in the circuit and when Q1 is high what is vbin and vout and also when Q1and Q2 are on what is the value of vbin and voutoBelow is the simulation of a circuit, as Scott suggested, with a 555 clock, a binary counter, and an R-2R ladder network with an op amp and transistor buffer output that gives ten 1V, 1 second steps and then repeats.
Is that more or less what you want?
Edit: The +12V power and ground connections to the counter and the AND gate are not shown.
Note that for best accuracy/stability you can use two 10kΩ resistors in series to make the 20kΩ resistance values. That also simplifies the part's list, although at the expense of more parts.
View attachment 71799
please what is the values of vbin at different steps and also vout and what is the REASON of USING the transistorBelow is the simulation of a circuit, as Scott suggested, with a 555 clock, a binary counter, and an R-2R ladder network with an op amp and transistor buffer output that gives ten 1V, 1 second steps and then repeats.
Is that more or less what you want?
Edit: The +12V power and ground connections to the counter and the AND gate are not shown.
Note that for best accuracy/stability you can use two 10kΩ resistors in series to make the 20kΩ resistance values. That also simplifies the part's list, although at the expense of more parts.
View attachment 71799
The value for Vbin is shown on the graph and is approximately .747 of the desired Vout which is why the op amp has a gain of 1.338. The Vout steps are 1V.please what is the values of vbin at different steps and also vout and what is the value of the transistor
sorry i mean the reason of using the transistorthe value for vbin is shown on the graph and is approximately .747 of the desired vout which is why the op amp has a gain of 1.338. The vout steps are 1v.
What do you mean by "value of the transistor". It's shown as a 2n2222 but most small npn transistors will work. Its purpose is to provide more output current than the op amp can supply.
Note that the circuit i posted cycles continuously. If you need it to stop at the end and return to 0v (or stay at 10v) until a switch is actuated to repeat the cycle, then i can modify the circuit for that.
The transistor is a voltage follower to boost the output current since the 5mA you mentioned may be near the limit of what the op amp can deliver. But if the output load is never lower than 2kΩ you can eliminate the transistor and just connect R15 directly to the op amp output.sorry i mean the reason of using the transistor
by Duane Benson
by Duane Benson
by Aaron Carman
by Aaron Carman