States of an atom in spectral notation

Thread Starter

circuit2000

Joined Jul 6, 2006
33
I solved in the following way:
For d electron,
Orbital angular momentum quantum number(L)=2
Spin angular momentum quantum number(S)=1/2
Possible values of total angular momentum quantum number(J)= L+S,| L+S-1|,…,|L+S|
Hence,
J= (2+1/2), |2+1/2-1|,|2-1/2|
J= 5/2,3/2,1/2
Possible states of the atom in spectral notation are,
2 D 5/2, 2 D 3/2, 2 D ½
But the answer given in my book is 2 D 5/2, 2 D 3/2.
 

Thread Starter

circuit2000

Joined Jul 6, 2006
33
Sorry, I forgot to give the question.
1)Give in spectral notation the possible states of an atom which has a closed core plus one d electron.

I solved in the following way:
For d electron,
Orbital angular momentum quantum number(L)=2
Spin angular momentum quantum number(S)=1/2
Possible values of total angular momentum quantum number(J)= L+S,| L+S-2|,…,|L+S|
Hence,
J= (2+1/2), |2+1/2-2|,|2-1/2|
J= 5/2,1/2,3/2
Possible states of the atom in spectral notation are,
2 D 5/2, 2 D 3/2, 2 D 1/2
But the answer given in my book is 2 D 5/2, 2 D 3/2.
 
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