Spark Plug Question

Discussion in 'Homework Help' started by electrical_ck, Jan 9, 2010.

  1. electrical_ck

    Thread Starter New Member

    Dec 7, 2009
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    0
    Hi there I encountered the following question:

    If a coil in a car has an inductance of 5 H and the rate of change of current is 4000 A/s, what is the induced voltage at the spark plug?

    Was wondering how the heck am I suppose to figure this out?

    I got this formula vl = L (il/t)

    vl= induced voltage across the coil
    L = Inductor
    il= current
    t = time

    so 5 (4000/1) = 20kV this correct?
     
  2. SgtWookie

    Expert

    Jul 17, 2007
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  3. electrical_ck

    Thread Starter New Member

    Dec 7, 2009
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