Hi there I encountered the following question:

If a coil in a car has an inductance of 5 H and the rate of change of current is 4000 A/s, what is the induced voltage at the spark plug?

Was wondering how the heck am I suppose to figure this out?

I got this formula vl = L (il/t)

vl= induced voltage across the coil
L = Inductor
il= current
t = time

so 5 (4000/1) = 20kV this correct?

 

Yes.

More reading:
http://www.techlearner.com/DCPages/DCInd.htm
http://en.wikipedia.org/wiki/Inductor

 

Yes.

More reading:
http://www.techlearner.com/DCPages/DCInd.htm
http://en.wikipedia.org/wiki/Inductor

thanks for the help