# Source-Superposition

Discussion in 'Homework Help' started by katchat64, Oct 7, 2010.

1. ### katchat64 Thread Starter New Member

Oct 7, 2010
2
0
Determine the current Ix in the circuit by applying the source-superposition method. Call I'x the component of Ix due to the voltage source alone, & I''x the component due to the current source alone. Show that Ix = I'x + I''x.

I got the circuits converted, but I am having trouble on what to use to solve for I'x and I''x.

http://s215.photobucket.com/albums/cc118/katchat64/?action=view&current=untitled.jpg

Here is the image of the circuits, if you have trouble please let me know. Thank you. In the drawings I accidentally labeled the I'x and I''x in the wrong circuits. I''x should be in the second circuit and I'x should be in the third circuit.

Last edited: Oct 7, 2010
2. ### R!f@@ AAC Fanatic!

Apr 2, 2009
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did ever try doing it yourself before asking?

3. ### katchat64 Thread Starter New Member

Oct 7, 2010
2
0
well let's see then yes I did... but I know that my work is wrong therefore, there isn't a motive for me to post up work that is incorrect.

I'm having trouble with whether or not I am able to combine the resistors, but I think that that would change the current. Is this so, if not then that means that I can use a Y-transformation to convert the middle into a phi circuit and from there combine all of the parallel or series resistors together.

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