Determine the current Ix in the circuit by applying the source-superposition method. Call I'x the component of Ix due to the voltage source alone, & I''x the component due to the current source alone. Show that Ix = I'x + I''x.

I got the circuits converted, but I am having trouble on what to use to solve for I'x and I''x.

http://s215.photobucket.com/albums/cc118/katchat64/?action=view&current=untitled.jpg

Here is the image of the circuits, if you have trouble please let me know. Thank you. In the drawings I accidentally labeled the I'x and I''x in the wrong circuits. I''x should be in the second circuit and I'x should be in the third circuit.

 

did ever try doing it yourself before asking?

 

well let's see then yes I did... but I know that my work is wrong therefore, there isn't a motive for me to post up work that is incorrect.

I'm having trouble with whether or not I am able to combine the resistors, but I think that that would change the current. Is this so, if not then that means that I can use a Y-transformation to convert the middle into a phi circuit and from there combine all of the parallel or series resistors together.

 

Review http://www.allaboutcircuits.com/vol_1/chpt_10/7.html to make sure you understand superposition.

The rules maintain that you supply your efforts so the members can assist you fully.

 

And here are the formulas for Y do Delta transformation for the middle circuit:
http://www.allaboutcircuits.com/vol_1/chpt_10/13.html