Can someone tell me how I would go about finding the voltage through R5 using the source equivalent method. I still dont really understand this method.
So first you need is to disconnect R5 and then find Vth voltage.
To find Vth we could use superposition
Vth'1
Vth'2
Vth = Vth'1+Vth'2
Next we replace all voltage sources with short circuits, and all current sources with open circuits.
And calculate the resistance between terminals A - B
The question says determine the Thévenin equivalent circuit of the above network using the “source equivalent” method. Hence calculate the load voltage vL.
I assumed that you would reduce the circuit to one source with one resistance.
They is essentially the same, but I see two ways to solve this.
You can use the supperposition theorem to find the components of the voltage across the R5, nullifying all the sources but one each time. I trust you know how to do this.
The other way, which I think is what your tutor wants you to do, is to break the circuit to smaller pieces, merging all the sources, two at a time.
For example, starting from the left, find the Norton equivalent of R1 and V1. This will give you a resistance and a current source in parallel. That current source will be parallel with I1 and those can be combined.
Work this way, switching between Norton and Thevenin equivalents, until you reach R5.