can anyone please help me with this h.w question espiacally number 2 because I have to confirm my answers...If possible showing your working I would really appreciate it

1)What is the reading of the milliammeter when the load resistor RL is shorted ?
2)What are the readings of thje milliammeter when the loadresistor RL is set to each of the following values 50ohms and 50kiloohms ?
3With respect to part (ii), which value of RL makes the current source appear stiff ?

 

Hello,

There is a current source, the current will split over the two resistors.
The total current will always be 1 mA.

When RL is shorted, all current will go through the meter.
The other cases the current is split.
Keep in mind the lower the value of the sesistor, the higher the current.

Greetings,
Bertus

 

Hi !!

I need more explanation please espaically number 2

 

Hello,

There are some ways to do this.
One way is calculate the total resistance. (Rtot = ( 1 / (1/RS + 1/ RL))
Then calculate the voltage across the resistors. ( U = I * Rtot )
Then calculate the curren in each resistor. ( IL = U / RL ) and ( IS = U / RS )

Greetings,
Bertus