hello !!!

I am still new to this forum.i have encountered an ohms law question can anyone tell me how shall i work this question it might be really easy for you but for me its a bit complicated considering that i have just started studying electronics..... check this out !!!

 

First find the equivalent resistance of the two 10 ohm parallel resistors which is 5ohms. Then add it with the two other 10 ohm resistors which are in series with it to get 25 ohms. The current is 2A and thus the voltage is 2*25=50V

 

hi !!
Thanks but now I need to find
1)The voltage across the parallel resistors
2)the power dissipated in resistor A if the value of each resistor was doubled ??

 

What values have you been able to calculate?

 

I was able to find the voltage across the whole circuit but the question is that I have to find the voltage across the parallel resistors only and I found total resistance, I have to find .....

1)The voltage across the parallel resistors
2)The power disspated in resistor A if the value of each resistor was doubled

 

Given the total current of 2 amps, what voltage is across each of the resistors?

Hint: E = IR

 

hello !!
I'll give it atry someone confirm it please ...
V=IR
V=2*5
V=10V
But I still have question 2 please someone help me

 

Each element in a series circuit has the same current through it - so each will have a separate voltage drop.

Our Ebook has some valuable information for you - http://www.allaboutcircuits.com/vol_1/chpt_5/1.html.

 

hi !!!

I am still confused the current is 4 amps than
V=IR
V=4*5
V=20v

someone confirm it please !!

Thanks

 

Hello purecilia,
If the value of resistors are doubled then the current would reduce by half as the voltage is constant.
And then calculate the power using any of the formulae given here
http://www.allaboutcircuits.com/vol_1/chpt_2/4.html.
Hope this answers your second question.