Solve for RL circuit

Discussion in 'Homework Help' started by pokkedief, Jul 24, 2011.

  1. pokkedief

    Thread Starter New Member

    Jul 24, 2011
    2
    0
    I am completely lost with this AC question. Determine the value of Ls and Lp, equivalent frequency of 250k rad/s Rs = 300 ohms Rp = 600 ohms i am completely confused someone help me please. [​IMG] [/URL]
     
    Last edited: Jul 24, 2011
  2. blah2222

    Well-Known Member

    May 3, 2010
    554
    33
    I am assuming there are two cases where a resistor is in series with an inductor as well as the case where it is in parallel with an inductor.

    Please be clear about what you are asking and specifically having trouble with so we can help you.
     
  3. pokkedief

    Thread Starter New Member

    Jul 24, 2011
    2
    0
    i posted the picture of the circuit.
     
  4. blah2222

    Well-Known Member

    May 3, 2010
    554
    33
    Okay so what this question is asking you is: At what values of Ls and Lp will both circuits have the same impedance value at 250 krad/s?

    One is a series circuit and the other is a parallel circuit. Both impedances will be the same, and operate at the same frequency. Start by writing out the equations for both impedances and equate them.
     
  5. narasimhan

    Member

    Dec 3, 2009
    72
    6
    use this formula
    Rs+jwLs=(Rp)(jwLp)/(Rp+jwLp)
    Substitute w=250 Krad/s
    Rs=300 ohm and Rp=600 ohm
    and equate the real and imaginary parts separately.
    If you still don't understand then I'll give the whole solution.
     
  6. narasimhan

    Member

    Dec 3, 2009
    72
    6
    Actually I just explained what blah2222 has stated. The Rs+jwLs is the series circuit impedance and (Rp)(jwLp)/(Rp+jwLp) is the parallel circuit impedance and you should equate the two as I have done.
     
Loading...