Single-Phase Uncontrolled Full-Wave Rectifier (Resistive Load)

Discussion in 'Homework Help' started by kenny-one, Feb 23, 2011.

  1. kenny-one

    Thread Starter Member

    Apr 21, 2010
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    0
    hi guys.

    so i have this equation which i have attached, so i am asked to prove/verify that is correct, meaning i have to know the source equation and derive until i get to this point(as in the figure attached).

    pls help guys. thanks a lot.
     
  2. Georacer

    Moderator

    Nov 25, 2009
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    1,266
    The RMS voltage on a diode is defined as \sqrt{\frac1T \int_0^{T/2} V(t)^2 dt}
    and the RMS voltage on the output os \sqrt{\frac1{T/2} \int_0^{T/2} V(t)^2 dt}because it is rectified and has half the period of the original.
    As for the diode peak current, it is max(V(t))-0.7, essentially max(V(t))=Vpeak.

    Can you work a relation between those quantities?
     
  3. kenny-one

    Thread Starter Member

    Apr 21, 2010
    37
    0
    thanks for helping.

    So i tried to derive some equations, and i got the following:

    -if we consider the source voltage to be(as in the figure in attachment2), then, the diode rms voltage and output(rms) in relation to the voltage source are(as in the figure in attachment1).

    -My question: what is the relation between Vrms,diode and Vpeak,diode? from here i can go by solving the currents.

    thanks again.
     
  4. Georacer

    Moderator

    Nov 25, 2009
    5,142
    1,266
    Well, you know that for an ideal diode, Vpeak_diode equals Vpeak_source. And you know the relation between Vpeak_source and Vrms_source. That, along with your attachment no1, gives you your answer.
     
  5. kenny-one

    Thread Starter Member

    Apr 21, 2010
    37
    0
    oh, ya i got it...thanks a lot
     
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