# Single phase bridge rectifier

Discussion in 'Homework Help' started by jobu180, Feb 5, 2009.

1. ### jobu180 Thread Starter New Member

Nov 1, 2008
7
0
Hello,

Looking for some help with the following problem:

A single phase bridge rectifier output voltage is |118*1.414*sin(120*pi*t). Find the RMS value, period, and the DC component of this voltage.

I have the RMS (118 V) and period (1/60 seconds). I'm struggling with the DC component. Any ideas?

Thanks

2. ### mik3 Senior Member

Feb 4, 2008
4,846
63
Do you mean its input is 118*1.414*sin(120*pi*t)?

Apr 5, 2008
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4. ### jobu180 Thread Starter New Member

Nov 1, 2008
7
0
Nope. The problem reads output voltage...

5. ### mik3 Senior Member

Feb 4, 2008
4,846
63
The output of a rectifier is not a sinewave but anyway. The DC voltage of a full wave rectifier equals:

Vdc=2*Vm/pi

where Vm is the peak output voltage

6. ### jobu180 Thread Starter New Member

Nov 1, 2008
7
0
Mik3 Thanks. I know that's why I'm confused.

7. ### Cabwood Member

Feb 8, 2009
20
0
There's a modulus bar at the beginning of the expression, but not at the end. I think it should be:

| 118*1.414*sin(120*pi*t) |

Then the question makes sense, and the output is indeed as expressed.

8. ### mik3 Senior Member

Feb 4, 2008
4,846
63
In this way yes, it is correct.

9. ### loudteeshirt New Member

Oct 10, 2009
1
0
Hi..I am new and found this really great forum. Thanks

I need help on my church guitar amp on the power transfomer. Here is the line :

Main AC input 220AC -->power transformer --> single phase rectifier-->output 22Vdc.

The problem is I dont know what is the power transformer's step down voltage? Why it does not say any info on the transformer plus its already been thrown away. I have attached the schematic of the amp.

Many thanks.
Jimmi

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Last edited: Oct 10, 2009