The 147 is a 10-line to 4-line priority encoder. It basically converts the 1 of 10 into binary (BCD in this case). The 4511 converts the BCD into seven-segment to drive the display LEDs.You need at least 3 chips to do it. A LS147, 4049 and 4511.
Allen
This assumes that the 'black box' outputs and active low and that each output is able to drive 8 LEDs.The 147 is a 10-line to 4-line priority encoder. It basically converts the 1 of 10 into binary (BCD in this case). The 4511 converts the BCD into seven-segment to drive the display LEDs.
Of course you could leave out the intermediate BCD. Simply convert the 1-of-10 directly into 7-segment. In fact in your case (where you already have something that can drive LEDs) you could do this with a number of diodes. Probably quite a lot of diodes actually!
I have drawn the circuit for the zero output. The other outputs are similar. Because the "0" display needs 6 segments to be lit, 6 diodes are needed. For the "1" display only 2 diodes are needed, etc.
I agree! This is the low-tech solution.This assumes that the 'black box' outputs and active low and that each output is able to drive 8 LEDs.
A microcontroller would be much easier.
Do you have a programmer for any microcontroller?Anyone know of a "1 of 10 to 7seg. display" in a single ttl or cmos chip.
What if you have more than one LED on at the same time... such as your photo showing all LEDs on.Anyone know of a "1 of 10 to 7seg. display" in a single ttl or cmos chip.
Making a 10 led repeater for a remote display. Might be nice to read out numbers 0-9 if it's simple.
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Sounds like a good place for a PROM or EPROM. At least 1K x 8.Anyone know of a "1 of 10 to 7seg. display" in a single ttl or cmos chip.
Making a 10 led repeater for a remote display. Might be nice to read out numbers 0-9 if it's simple.
View attachment 115845