Simply RLC question

Discussion in 'Homework Help' started by de1337ed, Apr 3, 2012.

  1. de1337ed

    Thread Starter New Member

    Mar 6, 2011
    23
    0
    I'm really stuck on this simply RLC circuit problem:

    If I have a series RLC circuit with the Vs(t) source how do I find i_{l}(t) (current through the inductor)?

    I have the following parameters:
    Vs(t) = 5sin(10^{4}t) at t>0;
    R=1250Ω
    L=1.25mH
    C = 5nF.

    After doing KVL's, I keep ending with an equation for Vc(t), and not inductor current. I know that there is some trick that I'm not thinking of, but right now I can't figure it out. Help Please
    Thank you.
     
  2. daviddeakin

    Active Member

    Aug 6, 2009
    207
    27
    Are the components in series or parallel?

    Either way you can find the impedance of the network and then apply Ohm's law, i=v/Z
     
  3. eng.mustafasalah

    Member

    Nov 10, 2011
    41
    2
    hi
    u have w=10^4
    so .. u can fiend impedance z=R+Xl+Xc
    Xl=2*pi*w*L
    Xc=1/2*pi*w*C
    then fiend the total current
    the total current = the current through the inductor !! because the impedance are connected on series
    the current in series is
    It=IR=IXl=IXc
     
Loading...