hi
can someone help me in simplifying this expression:

(v'+u+w)(wx+y+uz')+(wx+uz'+y)

and another one:

(w'+x)yz'+(w''+x')yz'

...coz i'm not sure with my answers..
i badly needed it now... tnx

 

the second 1 is damn simple
yz'(w+w'+x+x')
2yz'

for the 1st one open the bracket and apply properties of boolean

 

Hi,

the second 1 is damn simple
yz'(w+w'+x+x')
2yz'

for the 1st one open the bracket and apply properties of boolean

1+1 = 1 and hence it must be yz'.
And for the first one expand the terms and try simplifying applying the rule
A+A' =1

 

wxv' + yv' + uz'c' + wxu + uy + uz' + wx + wy + wuz' + wx + uz' + y

y(1+v'+u+w) + wx(1+v'+u) + z'u(1+v'+w)

y + wx + z'u