Simplification?

Thread Starter

jared11378

Joined Oct 29, 2008
11
Does this look like its simplified as far as it can be? I wasnt sure if I was missing something.

((A'+B+C+D)'(AB'C'D)')'
((A'+B+C+D)')' + ((AB'C'D)')'
A'+B+C+D + AB'C'D
 

mik3

Joined Feb 4, 2008
4,843
A'+B+C+D + AB'C'D

from your last expression above you can take D as a common factor and make it like this:

A'+B+C+D(1+AB'C')

also (1+AB'C')=1

thus you can simplify it more

A'+B+C+D
 
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