Simplification problem

Discussion in 'Homework Help' started by YYZ, Dec 20, 2009.

  1. YYZ

    Thread Starter New Member

    Dec 20, 2009
    3
    0
    Hi I'm trying to simplify this expression but I have no idea where to start (image attached):
     
  2. Fraser_Integration

    Member

    Nov 28, 2009
    142
    5
    Look into DeMorgan's Theorems in the on line textbook
     
  3. Fraser_Integration

    Member

    Nov 28, 2009
    142
    5
    I think it simplifies to (A + B)(A' + B')
     
  4. YYZ

    Thread Starter New Member

    Dec 20, 2009
    3
    0
    Sorry, the actual question was prove that it is equal to A.B' + B.A'. Yeah I'll check out that link thanks guys :)
     
  5. YYZ

    Thread Starter New Member

    Dec 20, 2009
    3
    0
    I think I have done it, but can you check my working out (I did it on paint because some of it is quite messy):
     
  6. Ratch

    New Member

    Mar 20, 2007
    1,068
    3
    XYZ,

    You can download the program featured on the link below, and find the minterms of just about any logic expression you care to key in. From the minterms, you can simplify the expression with a Karnaugh map if necessary. It won't show you the derivation of the minterms, but you can use it to check your worked out answer. If the minterms of your simplification do not match the original problem, then your solution is wrong.

    Ratch

    http://forum.allaboutcircuits.com/showthread.php?t=22347&highlight=logic+lovers
     
Loading...