Hello members of the All About Circuits forum!
I am quite confused with boolean algebra and I have to simplify this:
SF + PB + DM + DB = 1
Would the simplification process be:
SF + PB + DM + DB = 1
SF + PB + D(M + B) = 1
SF + PB + B(M + D) = 1
SF + B(P +M + D) = 1
is this correct? If not, could you explain where I've gone wrong? thanks,
Ollie
I am quite confused with boolean algebra and I have to simplify this:
SF + PB + DM + DB = 1
Would the simplification process be:
SF + PB + DM + DB = 1
SF + PB + D(M + B) = 1
SF + PB + B(M + D) = 1
SF + B(P +M + D) = 1
is this correct? If not, could you explain where I've gone wrong? thanks,
Ollie