Hello,
I'm working on a small RF project that requires 2.4 volts. For testing I'm trying to rig the device up to a power adapter that I cannibalized from some old computer equipment. The power adapter outputs 5 volts DC, so based on some voltage divider circuits I found online I was able to drop the voltage to 2.4 volts using two resistors.
The problem is, the device simply doesn't turn on when connected to the power adapter, but does when connected to batteries. I've verified the power adapter is putting out 2.4 volts on the dot, so I'm at a loss to see what the matter could be; I'm assuming it must be the current.
Assuming it is the current, would the problem be the current is too high, or too low? I'm guessing it's too low since the circuit hasn't been fried when attempting to use the power adapter with it... so if my assumption is correct and the current is too low, I guess my question is:
How can you reduce the voltage of a circuit, but meanwhile retain the original current?
Hope this question isn't too obvious, heh
Thanks!
Dave
I'm working on a small RF project that requires 2.4 volts. For testing I'm trying to rig the device up to a power adapter that I cannibalized from some old computer equipment. The power adapter outputs 5 volts DC, so based on some voltage divider circuits I found online I was able to drop the voltage to 2.4 volts using two resistors.
The problem is, the device simply doesn't turn on when connected to the power adapter, but does when connected to batteries. I've verified the power adapter is putting out 2.4 volts on the dot, so I'm at a loss to see what the matter could be; I'm assuming it must be the current.
Assuming it is the current, would the problem be the current is too high, or too low? I'm guessing it's too low since the circuit hasn't been fried when attempting to use the power adapter with it... so if my assumption is correct and the current is too low, I guess my question is:
How can you reduce the voltage of a circuit, but meanwhile retain the original current?
Hope this question isn't too obvious, heh
Thanks!
Dave