ok i dont see how is the voltage divided between the 2 and 5k resistors. going into the terminals in this operational amplifier circuit
-----R (2k)--- (-) inverting
|
-----R(5k)---- (+) noninverting
|
3v
|
-----------
the rest i know how to do, im just not sure how many vols goes through each resistor
Thanks for your help
-----R (2k)--- (-) inverting
|
-----R(5k)---- (+) noninverting
|
3v
|
-----------
the rest i know how to do, im just not sure how many vols goes through each resistor
Thanks for your help