# Simple ODE

Discussion in 'Math' started by boks, Nov 28, 2008.

1. ### boks Thread Starter Active Member

Oct 10, 2008
218
0
y'(t) - ay(t) = 0

What is the form of the solution? $C \cdot e^{at}$

?

I have this ODE:

$T'(t) - (1 - \frac{n^2}{4})T(t) = 0$

If I'm right, the solutions should be of the form

$C \cdot e^{(1- \frac{n^2}{4})t}$

My book, however, says

$C \cdot e^ {1- \frac{n^2}{4}t}$

Who's right?

2. ### blazedaces Active Member

Jul 24, 2008
130
0
Assuming that n is a constant, you're correct. Your book probably forgot to indicate the proper notation is all. I wouldn't rely too heavily on your books. Your books make mistakes too. Trust yourself sometimes too...

-blazed

3. ### boks Thread Starter Active Member

Oct 10, 2008
218
0
Brilliant.

y' = (y - x)^2

what's the form of the solution here?

I find it hard to determine the form of solution of differential equations.

4. ### blazedaces Active Member

Jul 24, 2008
130
0
You need to use substitution, look HERE.

Good luck,
-blazed