I'd like to use an NPN to switch a small load, either saturated or off.
In the attached circuit, +VBAT varies between 3V and 4.2V and the base logic operates at 2.8V.
I'm planning to use a BC817-40 (datasheet here).
My calculations are:
Ic = 4.2 / 10000 = 0.42mA
Ib = 2.8 / 4700 = 0.50 mA
I know it's not usual to have Ib>Ic, but with Hfe of approx 400, it'll be saturated!
If I'm reading the datasheet correctly, this condition should give:
Vce(sat) of 0.01v
Vbe(sat) of 0.5v
Does that all seem correct? Anything to watch out for with this circuit?
In the attached circuit, +VBAT varies between 3V and 4.2V and the base logic operates at 2.8V.
I'm planning to use a BC817-40 (datasheet here).
My calculations are:
Ic = 4.2 / 10000 = 0.42mA
Ib = 2.8 / 4700 = 0.50 mA
I know it's not usual to have Ib>Ic, but with Hfe of approx 400, it'll be saturated!
If I'm reading the datasheet correctly, this condition should give:
Vce(sat) of 0.01v
Vbe(sat) of 0.5v
Does that all seem correct? Anything to watch out for with this circuit?
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