I think I have the first few portions of this question correct, but I am unsure if I have the correct answer for the portion with the sin wave.
Is what I'm doing correct?
Is what I'm doing correct?
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Is what I'm doing correct?
Here's the solution they are giving in the manual.BTW - Your answers are correct.
Actually know that I think about it more, if I apply the signal at a time t1= pi and go to time t2 = t then the -2 goes away, right? Is this correct?Like all things electrical there will always be strange behavior that crops up from time to time. Depending at what point (time-wise) in the AC cycle you apply the input to the integrator you get a different result with respect to the transient behavior. Do you know what the difference might be?
So having there negative 2 there is okay, right?The constant term in the solution is a DC offset in the output. As you observed, this offset can be removed by changing the phase of the input. In fact if you make the input a simple cosine, rather than a sine function, the offset vanishes.
I have already said that your answer is correct - what more can I say?So having there negative 2 there is okay, right?
by Jake Hertz
by Jake Hertz
by Aaron Carman
by Jake Hertz