How can I solve for a constant when it's inside an inverse tangent? 20=Tan^{-1}(a/30) Thanks.
T Thread Starter tadm123 Joined Nov 20, 2013 43 Apr 24, 2014 #1 How can I solve for a constant when it's inside an inverse tangent? 20=Tan\(^{-1}\)(a/30) Thanks.
#12 Joined Nov 30, 2010 18,224 Apr 24, 2014 #2 Spell it out in English 20 degrees is the angle you find when you take the inverse tangent of (a/30) tan both sides of the equation tan 20 = a/30 30 tan 20 = a a = 10.919107 Proof: 10.919107 /30 enter arc tan = 20
Spell it out in English 20 degrees is the angle you find when you take the inverse tangent of (a/30) tan both sides of the equation tan 20 = a/30 30 tan 20 = a a = 10.919107 Proof: 10.919107 /30 enter arc tan = 20
studiot Joined Nov 9, 2007 4,998 Apr 24, 2014 #4 Spell it out in English Click to expand... That's a good approach if equations get to you.