Simple Circuit... Source Transformation

Discussion in 'Homework Help' started by cursed, Oct 3, 2010.

  1. cursed

    Thread Starter New Member

    Oct 3, 2010
    2
    0
    Solve for ix in the following circuit using source transformation:

    [​IMG]


    So here's what I did:

    [​IMG]

    I'm confused how I find ix now, unless I did something wrong...? Maybe I'm supposed to convert the current source to voltage? Can someone help ASAP? Thanks. :)
     
  2. Georacer

    Moderator

    Nov 25, 2009
    5,142
    1,266
    Firstly, you have calculated wrong the value of the resistor. When two resistor end up being parallelly connected, in order to find their equivalent you don't add them. The equivalent is R_{eq}=\frac{R_1\cdot R_2}{R_1 +R_2}.
    Addition only works for resistors connected in series.

    Also, when two current sources are connected in parallel, they can be replaced with a single current source with double the current rating.
     
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