signals, system, transform ch2 hw

Discussion in 'Homework Help' started by ish2k9c, Feb 13, 2014.

  1. ish2k9c

    Thread Starter New Member

    Feb 13, 2014
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    hello I need help on this hw. problem 2.4 edition 5

    (a) express y(t) as a function of x(t)
    (b) verify your result by checking at least three points in time.
    (c) express x(t) as a function of y(t)
    (d) verify the results of part (c) by checking at least three points in time

    [​IMG]
     
    Last edited: Feb 13, 2014
  2. tshuck

    Well-Known Member

    Oct 18, 2012
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    ...you should probably upload the problem statement too...
     
  3. shteii01

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    Feb 19, 2010
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    Mind readers have left the building.
     
  4. ish2k9c

    Thread Starter New Member

    Feb 13, 2014
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    ok, sorry i dont know how to upload a pic, how do i do it ?
     
  5. tshuck

    Well-Known Member

    Oct 18, 2012
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    Click "Post Reply" when viewing this thread, attach the file using the attachments manager (little paperclip icon), select the file, click "Upload", then click "Post Reply".

    If you want to embed the image, copy the link that is generated after uploading the file in the attachment manager and paste it in the popup that appears when you click the "Add image" button...
     
  6. ish2k9c

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    Feb 13, 2014
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  7. ish2k9c

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    Feb 13, 2014
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    hello i just posted the picture
     
  8. shteii01

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    Write out x(t).
     
  9. ish2k9c

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    Feb 13, 2014
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    thats the problem i dont understand it ??? i dont know how to approach it... :confused: :(
     
  10. shteii01

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    x(t) has 4 distinct intervals.

    Interval 1.
    -10 <= t < -3
    What is x(t) in this interval?

    Interval 2.
    -3 <= t < 4
    What is x(t) in this interval?

    Interval 3.
    4<= t < 8
    What is x(t) in this interval?

    Interval 4.
    8 <= t < 15
    What is x(t) in this interval?
     
  11. ish2k9c

    Thread Starter New Member

    Feb 13, 2014
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    i can see the intervals, do i suppose to solve for t ?
     
  12. ish2k9c

    Thread Starter New Member

    Feb 13, 2014
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    am i suppose to solve for t ? u(t+3) ???
    for the first one ? i have no clue!
     
  13. shteii01

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    Feb 19, 2010
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    I have been looking at it. And maybe I am wrong. The length of t is different for the two functions. x(t) is from -10 to 15. y(t) is from -15 to 15, so if x(t) is input to find y(t), then how do you find y(t) when x(t) does not exist in the interval from -15 to -10.
     
  14. NguyenDon

    New Member

    Feb 15, 2014
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    You will probably have to ignore the time interval t < -10 and just give y(t) from t > -10 .
     
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