Series Parallel RLC example in Chap 5

Discussion in 'Feedback and Suggestions' started by medimager, Jan 3, 2005.

  1. medimager

    Thread Starter New Member

    Jan 3, 2005
    1
    0
    To get Z of R//(L--C2), I used the

    1
    -------------------------------
    1 1
    --------- + -----------
    ZR Z(L--C2)


    where ZR = 1.523K <-90 degrees
    Z(L--C2) = 470<0 degrees

    I come up with an answer of 359<-90 degrees or 370- j14.073

    What am I doing wrong? I can't figure out how you got your answer for this in Chap 5 Series Parallel RLC.
     
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