Series Parallel Circuit

Discussion in 'Homework Help' started by Sam1, Nov 29, 2010.

  1. Sam1

    Thread Starter New Member

    Nov 29, 2010
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    0
    [​IMG]
    I have to calculate the resistance of the adjustable resistor whenthepower delivered to the 5 ohm resistor is 40W.

    Im just not sure where to begin, i know the voltage will be the same for the resisters in parallel but im not sure how to work out that voltage because im missing the variable resistance. And thus im not sure how to work out the current. Iv been looking at all of the equation triangles and cant find any that will help me, i think im just not sure what.
     
  2. mik3

    Senior Member

    Feb 4, 2008
    4,846
    63
    For the 5 ohm resistor to dissipate 40W, the voltage across it equals:

    V=sqrt(P*R)=sqrt(40*5)=14.14V

    This is the same voltage across the 20 ohm resistor.

    I will leave you do the rest. :p
     
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