three bulbs of ratings 60W, 80W and 100W are connected in series to work on 240V. Which bulb will burn most brightly?
Attachments
-
1.4 MB Views: 64
You say that the bulbs are connected in series to a 240V source, but your work specifies a voltage of 220V.three bulbs of ratings 60W, 80W and 100W are connected in series to work on 240V. Which bulb will burn most brightly?
You don't saw what voltage the three bulbs are individually rated at. If this is all the information that is given, you need to make some assumptions because I can pick voltage ratings for the three bulbs such that any one of the three would be the brightest when all are put in series. What's the simplest assumption that makes the problem solvable as given?three bulbs of ratings 60W, 80W and 100W are connected in series to work on 240V. Which bulb will burn most brightly?
Just having the largest voltage across it isn't a sufficient reason. After all, if they are all in parallel then they all have the same voltage across them and then the one with the least resistance will dissipate the most power. The argument needs to exploit the fact that they are in series.The 60 W bulb will be brighter, as it has the largest resistance,so will have the largest voltage across it,
your work shows a 40W instead of 60W,??
The answer is 40.The 60 W bulb will be brighter, as it has the largest resistance,so will have the largest voltage across it,
your work shows a 40W instead of 60W,??
But how can that be? First off, 40 is just a number. You need to pay attention to units. Assuming you mean 40W, you don't HAVE a 40W bulb to choose from. You have three options -- the 60W, the 80W, or the 100W bulb.The answer is 40.
Depends on what assumptions you make.So what do you suggest should be the answer?
Sorry, by mistake I took the wrong value.But how can that be? First off, 40 is just a number. You need to pay attention to units. Assuming you mean 40W, you don't HAVE a 40W bulb to choose from. You have three options -- the 60W, the 80W, or the 100W bulb.
If all the bulbs are rated for the same voltage, the lowest wattage bulb will be the brightest in series.So what do you suggest should be the answer?
@djsfantasi: Just enclose it in {tex} tags, as explained in this post.Note: Could not to save my life, get this to work with Tex!
[tex]W=I^{2}R
60=I^{2}R_{60}
80=I^{2}R_{80}
100=I^{2}R_{100}[/tex]
[tex]60 < 80 < 100
R_{60} ? R_{80} ? R_{100}[/tex]
by Aaron Carman
by Aaron Carman
by Aaron Carman
by Duane Benson