Hi,
If theres 2 capacitors in series, 10 mF and 1 mF , that should calculate to
.9 mF total. (yes...Im the new guy )
If input was 100v , that means charge Q = .9 x 100 = 90 mC
From what Ive learnt from the ebook each capacitor has individual voltages based on total charge so...
Q / 10mF = 9v
Q / 1mF = 90v
My questions being
1. Is breakdown voltage passed on to the smallest capacitor ?
2. For a given charge ,can voltage exceed the source ?
( as a spike / break down )
3. If voltage is increased to maximum that 10mF can handle will 1mF capacitor be facing break down ?
These may seem like simple questions to alot of you but I can tell you ,
theyre head scatches to me so any imfo you can throw at me will get me going in the right direction .
Massive THANKS
If theres 2 capacitors in series, 10 mF and 1 mF , that should calculate to
.9 mF total. (yes...Im the new guy )
If input was 100v , that means charge Q = .9 x 100 = 90 mC
From what Ive learnt from the ebook each capacitor has individual voltages based on total charge so...
Q / 10mF = 9v
Q / 1mF = 90v
My questions being
1. Is breakdown voltage passed on to the smallest capacitor ?
2. For a given charge ,can voltage exceed the source ?
( as a spike / break down )
3. If voltage is increased to maximum that 10mF can handle will 1mF capacitor be facing break down ?
These may seem like simple questions to alot of you but I can tell you ,
theyre head scatches to me so any imfo you can throw at me will get me going in the right direction .
Massive THANKS