Seems simple...but cant get the answer

Discussion in 'Homework Help' started by saranya, Feb 19, 2005.

  1. saranya

    Thread Starter New Member

    Feb 19, 2005
    2
    0
    Though I am familiar with kirchhoff's law and could solve most simple circuits, the following problem seems different. Any help is appreciated. Thanks.

    Problem:
    Four identical resistors ( R ) form 4 sides of a square. The ratio of the effective resistance between adjacent corners to that between opposite corner is

    a) 4 R B ) R/4 c) 3R/4 d) 4R/3
     
  2. pebe

    AAC Fanatic!

    Oct 11, 2004
    628
    3
    Assume each resistor=R. The resistance across opposite corners = R+R in parallel with R+R. So resistance across corners = R

    Between adjacent corners, R is in parallel with 3R (the other 3 resistors in series) = 3R/4

    So the ratio = R:3R/4
     
  3. saranya

    Thread Starter New Member

    Feb 19, 2005
    2
    0
    thanks pebe for the clarification; the phrasing of the question is clear now.
     
Loading...