Second Order Circuit Question

Discussion in 'Homework Help' started by Digit0001, May 21, 2011.

  1. Digit0001

    Thread Starter Member

    Mar 28, 2010
    89
    0
    Hi

    Can someone explain to me how they got tan() in the last couple of lines, when they are finding the peak time.
    View attachment tut7_sols.doc


    P.S
     
  2. jegues

    Well-Known Member

    Sep 13, 2010
    735
    43
    It seems as though they took the expression for \frac{dv_{c}}{dt} (i.e. equation (2)), and divided it by, -5cos(21.794t_{o}), which is reasonable because the other side of the equation is simply 0.

    I assume they are neglecting the exponential terms because t_{o} is very small. By this I mean,

    e^{t_{o}}, \quad t_{o} \approx 0 \Rightarrow e^{t_{o}} \approx 1
     
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