RUNNING LINEAR ACTUATOR without feed back

Thread Starter

ajitnayak87

Joined Dec 30, 2013
9
Dear all.

Here i am trying to do simple algorithm.I wanna formula to calculate actual position in algorithm

Desired angle calculation:
desired angle=-0.00227272727273x + 102.272727273 where x= (3600*hour)+(minute*60)

actual angle:actual actuator stroke is 600mm ,3.2mm/sec speed ,0.192mm/min. I wanted to run actuator from morning 7 AM to 18PM. approximately 11 hour/660 minutes,How can i convert this mm/min movement into 45 deg to -45 deg .

7AM assume deg :45 , 0mm actuator initial length
12:30 assume deg :0 , 300mm length
18:00 assume deg -45,600mm actuator final length

half code with desired angle.
Rich (BB code):
static int hh;
static int mm;
static int ss;
signed int  degree;
unsigned int TS;

static float slope= 0.00227272727273;
static float intercept=- 102.272727273;


void setup()
{
  Serial.begin(9600);
  hh=06;
  mm=45;
  
}

void loop()
{
  calc_min();
if(hh<24)
{
    Serial.print("HH-MM: ");
    Serial.print(hh);Serial.print(":");Serial.println(mm);
    TS=(3600*hh)+(60*mm);
    Serial.print("TS:");
    Serial.println(TS);
    degree=(TS*slope)+intercept;
    Serial.print("Desired Degree:");
    Serial.println(degree);
    Serial.println("..................");
}
  delay(1000);
  
  
}
void calc_min()
{

if(mm<60)
{
   mm=mm+5;
}else if(mm==60)
{
  mm=0;hh=hh+1;
}
}
 

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