RLC problem

Discussion in 'Homework Help' started by Furki, Mar 1, 2009.

  1. Furki

    Thread Starter Member

    Mar 1, 2009
    10
    0
  2. Furki

    Thread Starter Member

    Mar 1, 2009
    10
    0
    Sorry for being vague but

    What is the equation of the curve that joins the peaks of this wave(the one shown in the picture)?
     
  3. mik3

    Senior Member

    Feb 4, 2008
    4,846
    63
    The equation is:

    y=Aexp(-bx)

    Find the right values for A and b.
     
  4. mik3

    Senior Member

    Feb 4, 2008
    4,846
    63
    From the graph and the equation you have given it has to be:

    y=250*exp(-62.5t)
     
  5. Furki

    Thread Starter Member

    Mar 1, 2009
    10
    0
  6. Furki

    Thread Starter Member

    Mar 1, 2009
    10
    0
    Putting t = 26.4ms in y=250*exp(-62.5t) gives 48, it should give 59.2V according to the graph.

    btw,
    R = 500 ohms, L = 4H, C = 1 uF
     
  7. mik3

    Senior Member

    Feb 4, 2008
    4,846
    63
    Then use a point from the graph to calculate A.
     
  8. alwayslearning

    Member

    Feb 27, 2008
    22
    0
    You say your plot is marked at 2.5 Volts? It is actually marked at 59.2 Volts.
    If you desire to know the value of (t) at 2.5 Volts then specify at which time?

    Please specify the initial conditions-I took a guess as -->source is zero, i(0)=0.5 Amps and Vc(0)=377 Volts? Or
    di(0)/dt could also have been given instead as 94.24 assumming your A1, A2 are correct?
     
    Last edited: Mar 2, 2009
Loading...