Please show me the steps involved in answering the questions in the attached picture. Please and thanks for your time

https://forum.allaboutcircuits.com/attachment.php?attachmentid=65162&stc=1&d=1393117955

 

Just upload pic to imgur and link, or photobucket, or flickr, or whatever other pic hosting service.

(rhetorical question) Why such simple thing like posting a pic is such pain in the a$$? (end of rhetorical question)

 

Sorry about that http://imgur.com/x1dl95l

 

Part a.

*Replace inductors with jwL.
j is unit imaginary number
w=60 Hz, this is given to you when they told you about the source
L is inductance of the inductor, you only have one.

Replace capacitor with 1/(jwC)
j is same as above.
w=60 Hz
C is capacitance of the capacitor, you only have one.

Now you have calculated impedance of the inductor and capacitor. The unit of impedance is Ohm. Meaning, you replaced inductor and capacitor with their resistor equivalent. So now you have purely resistive circuit. Some of your resistors are in series, some in parallel. Find equivalent resistance, that is your total impedance of the circuit.

 

What do you mean by "imaginary number"? Are you referring to the component method?

I've gotten as far as determining XL=3.77ohms and XC=17.68ohms just not sure where to take it from there....

 

According to the answer sheet:
a) 3.55ohms
b)33.21
c)10.9 degrees lagging current
d)33.21amps
e)6.389amps

 

Do you mean j is -90 or 90 degrees?

 

What do you mean by "imaginary number"? Are you referring to the component method?

I've gotten as far as determining XL=3.77ohms and XC=17.68ohms just not sure where to take it from there....

XL and Xc denotes reactance. You need to take it a step further. You need impedance.

To answer your other question:
+j is 90°
-j is -90°

Also. 1/j is equal to -j. So 1/(jwC)=-j/(wC)

 

Part a.

*Replace inductors with jwL.
j is unit imaginary number
w=60 Hz, this is given to you when they told you about the source
L is inductance of the inductor, you only have one.

Replace capacitor with 1/(jwC)
j is same as above.
w=60 Hz
C is capacitance of the capacitor, you only have one.

Now you have calculated impedance of the inductor and capacitor. The unit of impedance is Ohm. Meaning, you replaced inductor and capacitor with their resistor equivalent. So now you have purely resistive circuit. Some of your resistors are in series, some in parallel. Find equivalent resistance, that is your total impedance of the circuit.

I am sure you meant f = 60Hz.

 

Ok yeah so impedance of LR1 is 6.262ohms and CR2 is 20.312ohms
Where do I go from there?

 

I am sure you meant f = 60Hz.

Yes, thank you.

w=2*pi*f=2*pi*60

 

Ok yeah so impedance of LR1 is 6.262ohms and CR2 is 20.312ohms
Where do I go from there?

That can not be right because I don't see j.

Also. I am sorry for making earlier mistake. w=2*pi*f
In your case f is given, it is 60 Hz.

 

This should help: http://hyperphysics.phy-astr.gsu.edu/hbase/electric/impcom.html#c1

 

This should help: http://hyperphysics.phy-astr.gsu.edu/hbase/electric/impcom.html#c1

That's exactly what I've been looking for thank you

 

I think the answers you posted in post number 6 has problems. Answers b and d can not be the same.

The others are suspect as well.