RLC Circuit

Discussion in 'Homework Help' started by k31453, May 22, 2013.

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  1. k31453

    Thread Starter Member

    May 7, 2013
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    [​IMG]

    This is my question 1.

    and this is my question 2.

    in a RLC series circuit show above are replaced following : R=500Ω L=0.4mH and C=100pF
    the circuit is connected to the terminals of an ac source with an rms voltage of 1V, and a variable frequency calculate the following
    A) resonant frequency
    ans: f = 1/2*pi*sqrt(LC)
    = 1/(2*pi*sqrt(0.0004 * 100 * 10^-12)
    = 795.77 Khz

    b) the inductive and capacitive reactance at resonance
    ans: XL = 2*pi*f*L
    = 2*pi* 795.775*10^3*0.0004
    = 2000 ohm

    Xc = 1/(2*pi*f*C)
    = 1/(2*pi* 795.775*10^3 * 100 * 10^-12)
    = 1999.9998 ohm

    C) the impedance at resonance

    ans : impedence of resonance is resistance of circuit : z = R = 500 ohm

    D) the rms current at resonance
    ans: I = V/R = 1/500 = 0.002A

    E) the rms voltage across each element at resonance
    Ans: Vr = IR
    = 0.002 * 500
    = 1V

    VL = IXL
    = 0.002 * 2000
    = 4V

    Vc = IXc
    = 0.002 * 1999.99
    = 3.99998 V

    So am i doing it right?? because
    i got another reply that says this :

    [​IMG]
    [​IMG]
     
  2. WBahn

    Moderator

    Mar 31, 2012
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    4,796
    If you want to go back and track your units, I will look through this. Otherwise it's not worth my time.
     
  3. k31453

    Thread Starter Member

    May 7, 2013
    54
    0

    yeah i know there is mistake he did he use 0.4H instead of 0.4mH
     
  4. Georacer

    Moderator

    Nov 25, 2009
    5,142
    1,266
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