RLC circuit, initial and final conditions.

Discussion in 'Homework Help' started by wiz0r, Oct 18, 2008.

  1. wiz0r

    Thread Starter Active Member

    May 2, 2008
    64
    0
    Hello!

    I got the following problem to solve(it is "circuito" in the attachment).

    So, I have to find the initial and final conditions of the RLC circuit.

    Ok, I have to evaluate at t = 0, and t = infinite, right?

    So, at t = 0 the first switch is open, the second one is closed, and the capacitor will act as an open circuit, and the inductor as a short circuit, right?

    Making some calcs I got that;

    i(0) = 8/3 Amps, is that correct?

    Now, at t = infinite, the first switch is closed, the second one is open, and the capacitor will act as an open circuit, and the inductor as a short circuit, right?

    So, with some calcs I got;

    i(infinite) = 5 Amps, correct?

    Anyway, I wanted to verify that what I did was correct. If I'm not correct, please post it and I will post my calculations, and then we can see what I did wrong.

    Please, help me.

    Thanks.
     
  2. Ratch

    New Member

    Mar 20, 2007
    1,068
    3
    wiz0r,

    Your analysis and results are both correct.

    Ratch
     
  3. wiz0r

    Thread Starter Active Member

    May 2, 2008
    64
    0
    Great, thank you, Ratch.
     
  4. hitmen

    Active Member

    Sep 21, 2008
    159
    0
    I have a question. How are you going to find Rth?? How are you going to find the differential equation?:confused:
     
  5. luna

    Member

    Oct 19, 2008
    12
    0
    the Rth you can find it like this:
    RL=Rth
    Rth=R2*R1/R1+R2
    but this is for Thevenin equvalent Circuits
     
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