1. diwa2000@gmail.com

    Thread Starter Active Member

    Apr 15, 2008
    40
    0
    Hello

    Could somebody suggest how could the output of the peak detector that has ripples be removed. I mean I want to remove the ripples ...does the ripples appear at 433MHz from the output of peak detector.

    please suggest.
    thanks
     
  2. diwa2000@gmail.com

    Thread Starter Active Member

    Apr 15, 2008
    40
    0
    please help to the above question. if any more data is needed please post back.
    thanks
     
  3. mik3

    Senior Member

    Feb 4, 2008
    4,846
    63
    Calculate R*C to be 10 times greater than 1/f

    where R=the resistor in parallel with the capacitor C
    C=the capacitor
    f=your frequency

    Are you sure you have 433 MHz frequency?
    What is your circuit built of?
     
  4. cumesoftware

    Senior Member

    Apr 27, 2007
    1,330
    10
    You can't remove the ripple entirely, but you can also use this formula:
    C = Iload / (Vripple * f) for an approximation.

    mik3's formula is correct considering 10% ripple (Vripple / Vtot = 0.1).
     
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