Calculate the value of the capacitor so that the average voltage on the load is 9.75 V.The current on R2 equals 0,2 A
If the input voltage has an amplitude of 10 V,therefore the ripple equals to 0,25V
\(
I*delta T=C*Delta V
0,2A*10ms=C*0,25V
C=8 mF
\)
Is this right?
Thanks
If the input voltage has an amplitude of 10 V,therefore the ripple equals to 0,25V
\(
I*delta T=C*Delta V
0,2A*10ms=C*0,25V
C=8 mF
\)
Is this right?
Thanks
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