resonance frequency of L C

Discussion in 'General Electronics Chat' started by VALKETEER, Mar 14, 2006.

  1. VALKETEER

    Thread Starter New Member

    Mar 14, 2006
    2
    0
    I have an electronics math problem that is driving me nutz.

    10vAC in series with a 10k resistor, a .5mH coil, and a 560pF capacitor. Question is what is the resonance frequency?

    Answer: 301 KHz

    Problem:
    1
    ---------------------------------
    Fr = 2Pi * square root(.5 mH * 560 pF)


    I get (9.5 kH) do you have an idea what step I’m missing?
     
  2. Papabravo

    Expert

    Feb 24, 2006
    10,135
    1,786
    I don't know where you went wrong, but here is my solution
    0.5 mH = 0.5e-3 Henry, and 560 pF = 560e-12 Farad
    Code ( (Unknown Language)):
    1.  
    2. Compute the denominator
    3. 2 * pi * √ (0.5e-3 * 560e-12) =
    4. 6.28 * √ (280e-15) =
    5. 6.28 * 529e-9 =
    6. 3.324e-6 and
    7. Take the reciprocal
    8. 1 / 3.324e-6 = 300.77e3 =
    9. 301 kHz
    10.  
    11.  
     
  3. VALKETEER

    Thread Starter New Member

    Mar 14, 2006
    2
    0
    Thanks, I see where I went wrong now.
     
  4. hgmjr

    Moderator

    Jan 28, 2005
    9,030
    214
    When I run the numbers through your expresssion, I get 300,774 Hz.

    hgmjr
     
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