resistor voltage drop

Discussion in 'General Electronics Chat' started by willdr, Aug 14, 2008.

  1. willdr

    Thread Starter New Member

    Aug 14, 2008
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    how is the voltage drop across a single resistor calculated? In a simple E Mosfet circuit from where are the measurements for Vg and Vd taken?
     
  2. SgtWookie

    Expert

    Jul 17, 2007
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    Ohm's Law:
    E = sqrt(PR), or Voltage = the square root of (Power in Watts x Resistance in Ohms)
    E = P/I, or Voltage = Power in Watts/Current in Amperes
    E = IR, or Voltage = Current in Amperes x Resistance in Ohms
    The reference is the source. It's usually specified (respectively) as Vgs and Vds or Vdss.
     
  3. willdr

    Thread Starter New Member

    Aug 14, 2008
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    I have 15v Vdd and one resistor 2.7 Kohms gong into a E mosfet and I measure 3.544v for Vd but have not been able to calculate it.
     
  4. SgtWookie

    Expert

    Jul 17, 2007
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    Why don't you post a schematic of your circuit?
    That's much easier than trying to describe it.
    As of this moment, I have no clue as to what your Vgs is, what MOSFET you're using, or even if it's N-ch or P-ch.
     
    Last edited: Aug 14, 2008
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