A pot can be a rheostat. It depends on how you wire it up. This fact leads to sloppy habits about how you use the words.I thought a rheostat would be better than a pot.
If you choose the pot solution, yes. Wire it as a rheostat. In series.I'll order 2 or 3 different pots when I have time this week considering your opinions. I'll make some tests and you will learn about my observations probably in a couple of weeks, maybe more. I thank you, Inwo and #12, for your advises and infos. You both agree about wiring the pot in series ?
I only see 5 watt pots in the link.I finally got time between interruptions to read the references.
Your reference in post #23 shows that a 5 ohm, 10 watt rheostat has a 2 amp limit. I calculate 1.4 amp The lamp alone will limit the current to 1.66 amps. Therefore, any setting of the rheostat can not have more than 1.66 amps and the 5 ohm, 10 watt rheostat will be safe under these conditions.
The curves on one of the graphs tells me that a 5 ohm, 5 watt rheostat I show 1 amp max hould survive, but with very little safety margin and the 10 ohm, 10 watt will also have this very slim safety margin.
This firms up my decision that 5 ohms, 10 watts is the right one of the 4 options I linked in post #12.
This link was good ?...Here are some at Digi-key for under $5
5 ohms, 5 watts should probably work unless you want to get very dim. Then choose the 10 ohm, 5 watt. You can experiment with fixed resistors to see whether you want 5 ohms or 10 ohms.
http://www.digikey.com/product-sear...t=0&page=1&quantity=0&ptm=0&fid=0&pageSize=25
Link is good, but only shows the 5 watt pots.This link was good ?...
I am tripping over one minor point in your drawing...Hi,
I try to make a simple electronic circuit.
So I have an instrument (medical ophtalmoscope) that contains a light bulb 10w, 6v. The adapter is noted 6v, 1.7A . I want to bypass the small rechargeable battery pack that isn’t working well. So I want to dim my bulb using a potentiometer. I tried a 100kΩ that was smoking (I chose that resistance because that's what is noted on the potentiometer of my original batt pack . So I guess there was a more complex assembly of resistors connected to it.)
My question: what is the ideal resistance needed for my potentiometer in this circuit (and does it have to be linear or logarithmic) ? I want the brightness to vary ok but not necessarily perfect. (A range of acceptable resistances would be fine ). I want it to work without burning it this time.
Thanks a lot,
You are right. It's a mistake. But trivial, as shorting load to ground isn't an issue.I am tripping over one minor point in your drawing...
What is the actual configuration of the contacts on your switch ?
It Appears to be a SPDT switch, which would dictate your battery + should be hooked up to the center spade, but then again, Looking at the switch rocker, says it is a sequential SPDT...
I am going to have to cobble up the circuit to know if you have it wired right... 'cuz somehow your drawing doesn't look right... A 2 watt pot should handle that all day long and then some...
Take that information from an experienced " pot smoker "
I did not execute what's on my drawing yet. Except for the pot (100k) connections. My question is still : what's the ideal pot for the parameters I mentioned ? If someone can give the right link to find it, it will help a lot. I'll create à box with connectors to the adaptor and the instrument. I may or may not add a switch. And I will find out how to wire that right.I am tripping over one minor point in your drawing...
What is the actual configuration of the contacts on your switch ?
It Appears to be a SPDT switch, which would dictate your battery + should be hooked up to the center spade, but then again, Looking at the switch rocker, says it is a sequential SPDT...
I am going to have to cobble up the circuit to know if you have it wired right... 'cuz somehow your drawing doesn't look right... A 2 watt pot should handle that all day long and then some...
Take that information from an experienced " pot smoker "