Hi, Sorry this is really simple and boring but a large resistor has burnt out on a very very simple circuit for charging a battery within a torch.
From a 6v DC (300ma) plug, the positive terminal goes through the large (probably 3 or 5W) burnt out resistor then through a 1N4007 Rectifier Diode which then splits off to the battery and the lamp. The battery requires: Cyclue use = 4.82-4.99V, Standby use = 4.5-4.6V and Max charging current of 0.84A.
The resistor is burnt beyond recognition, so I'm hoping someone wouldn't mind telling me the value of which i can replace it with (and remind me why). Also wether it would be better to go with a higher or lower value than this depending on what is available to me.
I greatly appreciate your time and help, I have attached a picture of said circuit and a (poor) diagram of the layout.
Thanks
From a 6v DC (300ma) plug, the positive terminal goes through the large (probably 3 or 5W) burnt out resistor then through a 1N4007 Rectifier Diode which then splits off to the battery and the lamp. The battery requires: Cyclue use = 4.82-4.99V, Standby use = 4.5-4.6V and Max charging current of 0.84A.
The resistor is burnt beyond recognition, so I'm hoping someone wouldn't mind telling me the value of which i can replace it with (and remind me why). Also wether it would be better to go with a higher or lower value than this depending on what is available to me.
I greatly appreciate your time and help, I have attached a picture of said circuit and a (poor) diagram of the layout.
Thanks
Attachments
-
229 KB Views: 38
-
229.1 KB Views: 38