relays help

Discussion in 'Homework Help' started by jav_, Mar 8, 2007.

  1. jav_

    Thread Starter New Member

    Nov 6, 2006
    2
    0
    im very confused on this one part of my assignment...
    what is supposed to happen is that when J2 closes (J1 is already closed), X1 lamp will turn on immediately and after 5 seconds X2 will turn on.

    i paralled X3 with X2 because X3 must be on when both X1 and X2 are turned on.

    i just cant seem to figure out where to place the TDE and control relay contacts to make this happen..

    can anyone help me out?

    thanks in advance!
     
  2. kender

    Senior Member

    Jan 17, 2007
    263
    0
    I have a descent guess on what the answer is. However, since this is a homework question, I'll rain some simple question on you first ;), because your description of the circuit is not entirely clear (at least to me).

    Here it goes. What's TDE and "TDE TC"? Is it a time delay circuit? How does TDE work, when it's turned off. If so, why does it appear as a capaciator in the schematic? Is the current AC or DC? What are the rails on left and right connected to? Are you trying to simlate the whole circuit (in OrCAD / PSpice) ?
     
  3. jav_

    Thread Starter New Member

    Nov 6, 2006
    2
    0
    its just a rough schematic diagram..its just a part of my whole circuit anyways...

    that thing that looks like a capacitor is actually a time close contact...
    so basically when the Time Delay relay energizes (i forgot to place the relay), that contact will close after 5 seconds
     
  4. kender

    Senior Member

    Jan 17, 2007
    263
    0
    Connect the left side of X1 directly to the right side of J2.
    Connect the left side of S2 to the right side of J2 also.

    This is too simple. I'm probably missing something.
     
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