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Papabravo

Joined Feb 24, 2006
21,226
You cannot replicate that "input power" 16 times without an additional supply; that would be an overunity design. With an additional supply you don't need the 10V @ 2.5 mA source.
 

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lordofentropy

Joined Apr 10, 2010
58
Sounds like you need to multiplex them with CMOS analogue switches.

Unbuffered from the 4000 CMOS family might do - but the RDSon could be a problem, and your signal mustn't exceed Vdd.

Other than that - there's whole families of industry standard analogue switch ICs that should provide a part that doesn't degrade signal integrity.
Unfortunately a switch will not due, because he wants to measure all of them at the same time, not switch through them. And having all connected to that channel (the 10V/2.5mA channel) would load down the box obviously.
 

AnalogKid

Joined Aug 1, 2013
11,055
I realize that this violates the "use the original 10 V source" condition, but

IF you just need a constant 10 V source
THEN you can replace the original source and the current buffer with an LM317 adjusted for 10 V

ak
 

AnalogKid

Joined Aug 1, 2013
11,055
Since your input does not provide a sink for the 2.5 mA of current, will the input still be +10V? I suppose you could add a 4K termination resistor if that will make a difference.
There still is a lot of ambiguity in the requirements. Is the 2.5 mA a minimum required output current, a max capable output current, or just the current required by the sensor? Don't know, but the circuit can be adapted.

ak
 

Papabravo

Joined Feb 24, 2006
21,226
There still is a lot of ambiguity in the requirements. Is the 2.5 mA a minimum required output current, a max capable output current, or just the current required by the sensor? Don't know, but the circuit can be adapted.

ak
Right. Since the poor fellow who made the original post is between a rock and a hard place; it seems only reasonable to toss out straws even if the relevance might be limited.
 
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