reading a log chart

Discussion in 'General Electronics Chat' started by jut, Jan 8, 2010.

  1. jut

    Thread Starter Senior Member

    Aug 25, 2007
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    [​IMG]
     
    Last edited: Jan 8, 2010
  2. StayatHomeElectronics

    Well-Known Member

    Sep 25, 2008
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    I would say Vds = 5V and Id = 3A.
     
  3. beenthere

    Retired Moderator

    Apr 20, 2004
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    I get 2 amps/4 volts.
     
  4. t06afre

    AAC Fanatic!

    May 11, 2009
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    I would also say Vds = 5V and Id = 3A.
     
  5. bertus

    Administrator

    Apr 5, 2008
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    Hello,

    I think it is 5 Volts and 3 Ampere;

    [​IMG]

    Greetings,
    Bertus
     
  6. Papabravo

    Expert

    Feb 24, 2006
    10,142
    1,790
    If you remember that 10^0 = 1 and each line between is one more than the previous one, it should be clear.

    The sequence of lines starting @ 10^0 is:
    [1,2,3,4,5,6,7,8,9,10] where 10 corresponds to 10^1
     
  7. VoodooMojo

    Active Member

    Nov 28, 2009
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    I get 3.5 volts and 2 amps
     
  8. Papabravo

    Expert

    Feb 24, 2006
    10,142
    1,790
    You've mistaken the parameter Vgs=3.5 volts for the Drain Source Voltage. The point at the arrowhead is at Vds=5V and Id=3Amps.

    Where'd you guys learn to read graphs?
     
  9. beenthere

    Retired Moderator

    Apr 20, 2004
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    Throw darts.
     
  10. VoodooMojo

    Active Member

    Nov 28, 2009
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    I cannot argue with that logic!
     
  11. mrmount

    Active Member

    Dec 5, 2007
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    Vdc=5V and Id=3A considering 10^0=1 and every sub-division after that is incremented by one.
     
  12. jut

    Thread Starter Senior Member

    Aug 25, 2007
    224
    2
    :confused:\Rightarrow:D

    Thanks all for the help.
     
  13. Wendy

    Moderator

    Mar 24, 2008
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    That's how I read it. They left off the 9V graticule.
     
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