hi !
I am wondering if I can look at RC lead phase inverter as a basic series and parallel circuits? The input has a series capacitor,C1 that is paralellel to a resister,R1 that is grounded.Another capacitor,C2 is in series which is followed by R2 and that resistor is grounded.And finally another C3 in series to a resistor,R3 which is grounded,which is the output,that is R3 .Would this be the correct view of this circuit?

 

Can you give a schematic?

The input has a series capacitor,C1 that is paralellel to a resister,R1 that is grounded

If the cap is in parallel with R1, then it, too, must be grounded. It can't be in series with the input.

 

You reduced it to a very small pic.

Change the format to .png and repost.

 

It's not parallel or series because it has 2 ports.
That is, you have a pair of input and and a pair of output terminals.

If you want a way to simplify this you need to use two-port network equations.

 

It's not parallel or series because it has 2 ports.
That is, you have a pair of input and and a pair of output terminals.

If you want a way to simplify this you need to use two-port network equations.

I am trying to understand if the total Impedance,Zt,for this circuit config. would be considered as the input impedance and the output Z, simutaneously, having the same impedance ? Or would the the frist two components of the config. input be considered as the input Z and the last two components of the config be the output Z.Also this is a two port network,input and output with a commom ground as I understand the concept.The config don't have voltage source but the last resistor is grounded,which makes the system closed on that end. The diagram is in two parts, the frist is just two of the components. I am taking in consideration the second diagram to the right,the three resistors and three capacitors in series and parallel connection.

 

The input impedance depends on your load, the output impedance depends on your source. They will be different.
For example, at DC the input impedance is infinite while the output impedance is just one resistor.

If there is no load then you can do series-parallel combinations and get a single equivalent impedance.

The system isn't "closed" on either end because you intend to attach things to both the input and output. If you never hook anything up to one side then yes, it's just series-parallel stuff but then input and output impedance wouldn't matter, it would just be a single equivalent impedance.

 

If there is no load then you can do series-parallel combinations and get a single equivalent impedance.

The system isn't "closed" on either end because you intend to attach things to both the input and output. If you never hook anything up to one side then yes, it's just series-parallel stuff but then input and output impedance wouldn't matter, it would just be a single equivalent impedance.

So regarding the RC phase shift, just calculating the Total Impedance is equated to the circuit attenuation? Do the total Z has something to do with the attenuation of the input voltage and output voltage and /or input current and output current?If nothing will be attached to both ends.

 

WEW!!, had sometime to learn the way.This is the diagram for the subject that we are discussing.But as the last reply stated ,"that the circuit automatically produce attention of voltage/or and current",and that you said, "that the input impedance depends on the load and the output impedance depends on the the source".Would the attenuation of the RC phase shift equivalent Ztotal change when it is attached as it is on the image that is attached to this post reply? Would the source be the output of the transitor collector?Would the transistor also be the load for the RC phase shift circuit? Is the phase shift the output impedance? WWaiting for someone to give forth some info.