Hi, this ain't homework though but i suspect something similar for a test.
Last week i had a similar practical about an active filter...
All i want to know is how to calculate the cut off freq of this 2stage filter with an Rload resistor.
circuit - http://i49.tinypic.com/rbwsoz.jpg
3db cut off - http://i49.tinypic.com/2em0qb4.jpg
Above are the practical results.
So the default equation goes Fc=1/(2∏RC)
I understand that Rs and R1 is in series but my equation and practical doesn't match up.
Fc=1/[(2∏(R1+Rs)//R2//R3)*(C1+C2)]
= 212 Hz
With orcad I get 122Hz. Can someone please help me with the theory cut off freq?
Thank you
Last week i had a similar practical about an active filter...
All i want to know is how to calculate the cut off freq of this 2stage filter with an Rload resistor.
circuit - http://i49.tinypic.com/rbwsoz.jpg
3db cut off - http://i49.tinypic.com/2em0qb4.jpg
Above are the practical results.
So the default equation goes Fc=1/(2∏RC)
I understand that Rs and R1 is in series but my equation and practical doesn't match up.
Fc=1/[(2∏(R1+Rs)//R2//R3)*(C1+C2)]
= 212 Hz
With orcad I get 122Hz. Can someone please help me with the theory cut off freq?
Thank you
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