To solve, I see there is parallel and series. I suppose the impedance formula will work, \(\sqrt{R^2}+{Xc^2}\) but what about the parallel part?
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Just v= I*R.Disregard the above post answer.
Q1) v = I*R = 33mA*180 ohms = 5.94v
The questions stated that it represents the current in the supply. Whatever the current is in the supply, that is what Io is equal to. It is simply a symbolic variable. How much algebra have you had so far.Q2) Io ? I don't know what this represents.
It should be -53.1 degrees (as a rule, carry three sig figs unless there is a good reason to do otherwise. For intermediate results, it is reasonable to carry at least one, but seldom more than two additional sig figs to minimize propagation of round off errors).Q3) \(z= \frac{333*250}{\sqrt333^2+250^2} =200 ohms\)
\( tan^-1* \frac{333}{250} = 53 degrees\)