RC Circuit

Discussion in 'Homework Help' started by Hitman6267, Jun 2, 2010.

  1. Hitman6267

    Thread Starter Member

    Apr 6, 2010
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    0
    question2.PNG
    answer2.PNG

    Can some one explain what they did ?
     
  2. mik3

    Senior Member

    Feb 4, 2008
    4,846
    63
    They found the voltage across both capacitors

    v=[1/(C1+C2)]*integral{i(t) dt}

    Then the current through C1 is:

    i1(t)=C1*dv/dt=[C1/(C1+C2)]*d/dt[integral{i(t) dt}=[C1/(C1+C2)]*i(t)
     
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